General Chemistry Chapter 6 (Chang)

Chemistry
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350J of heat are absorbed by system (425 cal of work done), compute changes in the internal energy & interpret the sign of your results.  

When 2.5 moles of N2(g) is heated in a piston, constant pressure of 2.25 atm 0ºC-->319ºC. Calulate work in J

Apr 7th, 2015

1.

350-425=-75J=change in internal energy, negative sign means the system lose 75J energy

2.

Since N2 is a diatomic gas. THus, the value of molar specific heat constant at constant pressure, Cp = 7R/2

where R = Universal gas constant = 8.314

Thus, Cp = 29.099

Now, work done = n*CP*dT ; where dT = change in temperature = 319

Thus, work done = 2.5*29.099*319 = 23206.453 J


Apr 7th, 2015

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Apr 7th, 2015
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Apr 7th, 2015
Dec 8th, 2016
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