Find the missing ∆H(rxn)

label Chemistry
account_circle Unassigned
schedule 1 Day
account_balance_wallet $5

            4B(s) + 3O2(g) ----> 2B2O3(s)                     ∆H(rxn) = -2509.1 kJ/mole

then, (i) 1/2 B2O3(s) ----> B(s) + 3/4 O2(g)              ∆H(rxn) = ?

         (ii) 16 B(s) + 12 O2(g) ----> 8 B2O3(s)            ∆H(rxn) = ?

Apr 7th, 2015
New Doc 7.pdf

Answers are (i) -627.275 KJ/mole

                      (ii) -100036.4KJ/mole


Please refer to doc for more details.

Please let me know if you have any questions and best me if you are satisfactory.

Apr 7th, 2015

List steps on how you derived both answers

Apr 7th, 2015

Please refer to the document in the link.

Apr 7th, 2015

Did you see that?

Apr 7th, 2015

Your the best!


Apr 7th, 2015

Thank You.

Apr 7th, 2015

Did you know? You can earn $20 for every friend you invite to Studypool!
Click here to
Refer a Friend
...
Apr 7th, 2015
...
Apr 7th, 2015
Jun 27th, 2017
check_circle
Mark as Final Answer
check_circle
Unmark as Final Answer
check_circle
Final Answer

Secure Information

Content will be erased after question is completed.

check_circle
Final Answer