Find the missing ∆H(rxn)

Chemistry
Tutor: None Selected Time limit: 1 Day

            4B(s) + 3O2(g) ----> 2B2O3(s)                     ∆H(rxn) = -2509.1 kJ/mole

then, (i) 1/2 B2O3(s) ----> B(s) + 3/4 O2(g)              ∆H(rxn) = ?

         (ii) 16 B(s) + 12 O2(g) ----> 8 B2O3(s)            ∆H(rxn) = ?

Apr 7th, 2015
New Doc 7.pdf

Answers are (i) -627.275 KJ/mole

                      (ii) -100036.4KJ/mole


Please refer to doc for more details.

Please let me know if you have any questions and best me if you are satisfactory.

Apr 7th, 2015

List steps on how you derived both answers

Apr 7th, 2015

Please refer to the document in the link.

Apr 7th, 2015

Did you see that?

Apr 7th, 2015

Your the best!


Apr 7th, 2015

Thank You.

Apr 7th, 2015

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