4B(s) + 3O2(g) ----> 2B2O3(s) ∆H(rxn) = -2509.1 kJ/mole
then, (i) 1/2 B2O3(s) ----> B(s) + 3/4 O2(g) ∆H(rxn) = ?
(ii) 16 B(s) + 12 O2(g) ----> 8 B2O3(s) ∆H(rxn) = ?
Answers are (i) -627.275 KJ/mole
Please refer to doc for more details.
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List steps on how you derived both answers
Please refer to the document in the link.
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