precalc. Arithmetic and geometric questions.

Calculus
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given the sequence 3, 6, 12, 24,.... find t11

Apr 7th, 2015

It is a geometric seies...

3 6 12 24 48 96 192 384 768 1536 3072

To find any term of a geometric sequence:

where a1 is the first term of the sequence, r is the common ratio, n is the number of the term to find.

here a1 = 3  and common ratio is 2   and we have to find 11th term so...n equals 11

a11 =  3 x 2^(11-1)

      = 3 x 2^10

       = 3 x 1024

Answer       =  3072

        


Apr 7th, 2015

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Apr 7th, 2015
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Apr 7th, 2015
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