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Physics
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A boat traveling at 22.4 m/s skids to a stop in 2.55 s. Determine the skidding distance of the boat.

Apr 7th, 2015

vi = 22.4 m/s

  vf = 0 m/s

  t = 2.55 s

  d = ?

*3 Sig. Digs. (There are several ways to do this question)

vav = ∆d  (Remember average velocity =  (vi + vf)

    ∆t    2

∆d = vav∆t

d = (vi + vf)t

    2

d = (22.4 m/s + 0 m/s)(2.55 s)

      2

d = (11.2 m/s)(2.55 s)

d = 28.6 m or 2.86 x 101 m


Apr 7th, 2015

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