A car is accelerated to a speed of 444 m/s in 1.83 seconds, then what is the acceleration and what is the distance that the car travels?

vi = 0 m/s

vf = 44 m/s

t = 1.80 s

Find:

d = ??

a = (444 m/s - 0 m/s)/(1.83 s)

a = 243 m/s2

d = vi*t + 0.5*a*t2

d = (0 m/s)*(1.83 s)+ 0.5*(243 m/s2)*(1.83 s)2

d = 0 m + 406 m

d = 406 m

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