Need physics help fast!@@@@@@@

Physics
Tutor: None Selected Time limit: 1 Day

A car is accelerated to a speed of 444 m/s in 1.83 seconds, then what is the acceleration and what is the distance that the car travels?

Apr 7th, 2015

vi = 0 m/s

vf = 44 m/s

t = 1.80 s

Find:

a = ??

d = ??

a = (Delta v)/t

a = (444 m/s - 0 m/s)/(1.83 s)

a = 243 m/s2

d = vi*t + 0.5*a*t2

d = (0 m/s)*(1.83 s)+ 0.5*(243 m/s2)*(1.83 s)2

d = 0 m + 406 m

d = 406 m


Apr 7th, 2015

Did you know? You can earn $20 for every friend you invite to Studypool!
Click here to
Refer a Friend
...
Apr 7th, 2015
...
Apr 7th, 2015
Feb 26th, 2017
check_circle
Mark as Final Answer
check_circle
Unmark as Final Answer
check_circle
Final Answer

Secure Information

Content will be erased after question is completed.

check_circle
Final Answer