A pizza car accelerates uniformly from rest to a speed of 7.10 m/s over a distance of 35.4 m. Determine the acceleration of the pizza car.

vi = 0 m/s

vf = 7.10 m/s

d = 35.4 m

Find:

(7.10 m/s)2 = (0 m/s)2 + 2*(a)*(35.4 m)

50.4 m2/s2 = (0 m/s)2 + (70.8 m)*a

(50.4 m2/s2)/(70.8 m) = a

a = 0.712 m/s2

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