How do I solve 2k2-7k+3=0

This is a quadratic equation ax^2 + bx + c = 0 with a = 2, b = -7, and c = 3.

Its solutions are (- b +/- sqrt{b^2 - 4ac}) / (2a) = (7 +/- sqrt{49 - 24}) / 4 = (7 +/- sqrt{25}) / 4 = (7 +/- 5) / 4.

Answer: The solutions are k_1 = 3 and k_2 = 1/2.

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