8. What is the molarity of a 5.00 x 102 ml solution containing 290 g of FeS2?
The molar mass of FeS2 is 55.845 + 2 * 32.06 = 120 g/mol. So, the number of moles of FeS2 in the solution is 290 g / 120 g/mol = 2.42 mol. The molarity of the solution is 2.42 / 0.500 L = 4.83 M
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