5. What is the molarity of a 2.50 x 102 cm3 solution containing 560.0 g of C6H12O6 ?
(560.0 g C6H12O6) / (180.1559 g C6H12O6/mol) / (0.250 L) = 12.43 mol/L C6H12O6 (2.50 L) x (30.5 mol/L) = 76.3 mol Sr(NO3)2
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