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What is the molarity of a 5.00 x 102 ml solution containing 2390 g of KI?

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What is the molarity of a 5.00 x 102 ml solution containing 2390 g of KI?

Apr 7th, 2015

solution :

Formula for molarity  =  ( number moles of  Kl )/ (Volume of the solution )

so  we have given , number moles of  Kl = 2390 g

  Volume of the solution  =  5.00 x 10^2 ml 

substituting the values in the formula  we have  

Molarity  =  2390 / 5.00 x 10^2      after  simplification  we  will get 

          =    4.78     your  final  answer  

thanks  

Apr 7th, 2015

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