Time remaining:
6. How many moles of Sr(NO3)2 would be used in the preparation of 2.50 L of a 3

Chemistry
Tutor: None Selected Time limit: 0 Hours

6.  How many moles of Sr(NO3)2 would be used in the preparation of 2.50 L of a 30.5 M solution?

Apr 8th, 2015

Each liter of 30.5 M solution contains 30.5 moles of strontium nitrate, so in 2.50 L there will be 

30.5*2.50 = 76.25 mol of Sr(NO3)2.

Apr 7th, 2015

Did you know? You can earn $20 for every friend you invite to Studypool!
Click here to
Refer a Friend
...
Apr 8th, 2015
...
Apr 8th, 2015
May 23rd, 2017
check_circle
Mark as Final Answer
check_circle
Unmark as Final Answer
check_circle
Final Answer

Secure Information

Content will be erased after question is completed.

check_circle
Final Answer