If each die has 6 values, then the total number of events is 6*6 = 36.
We may denote the events as (R1, B1), (R2, B1) etc.
For R1 we have no combined values that are > 7, for R2 there is only one such value: (R2, B6) etc.
So, there are 1 + 2 + 3 + 4 + 5 = 15 combined values that are greater than 7. The same number of combined values are less than 7.
The corresponding probabilities are 7/36.
PS. Let me know if the rules of the casino in question are different.
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