the size P of certain insect population at time t(in days) obeys the function P(t)=500e^0.02t if they have enough food and the predator population stays constant. After how many days will the population reach 1000?

Solve the equation 500 e^0.02t = 1000.

e^0.02t = 2; 0.02t = ln2; t = ln2 / 0.02 = 34.65... or in 35 days.

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