A sample of 49 observations is selected from a normal population. The sample mean is 61, and the population standard deviation is 6. Conduct the following test of hypothesis using the 0.10 significance level.
t = (61-63)/(6/7) = -2*7/6 = -7/3 = -2.333
Tabular value for 1% (two tailed) is 1.6772 for 48 df
| t | =2.333 > 1.6772
we reject the null hypothesis.
And conclude that mean is not equal to 63
How about this question What is the p-value?
P( |t| >2.333) = 0.0239
p value =0.0239
since 0.1 >0.0239 or 0.0239 <0.1 we reject the null hypothesis.
p value =0.0239 it says wrong
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