Help with General Chem

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1) Calculate ∆H(rxn) for N2H4(l) + O2(g) = N2(g) 2H2O(l)
2NH3(g) + 3N2O(g) = 4N2(g) + 3H2O(l) ∆H(rxn) = -1010 kJ/mole
N2O(g) + 3H2(g) = N2H4(l) + H2O(l) ∆H(rxn) = -317 kJ/mole
2NH3 + (1/2) O2(g) = N2H4(l) + H2O(l) ∆H(rxn) = -143 kJ/mole
H2(g) + (1/2) O2(g) = H2O (l) ∆H(rxn) = -286 kJ/mole
Apr 8th, 2015

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Apr 8th, 2015

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