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Mathematics

Description

Identify the null and  alternative hypotheses, test statistic, P-value, A simple random sample of25 filtered 100 mm cigarettes is obtained and the tart content of each is measured. The sample has a mean of 19.6 mg and a standard deviation of 3,43mg. Use 0.05 significance level to test the claim that the mean tar content of filtered 100mm cigarettes is less than 21.1 mg

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Explanation & Answer

Ho: u < 21.1 mg

Ha: u > 21.1 mg

test statistic z:

z = (19.6 - 21.1) / 3.43/√25

= -2.1866

using table of z-scores for alpha=0.05 we get

P-value = 1.6449

Since -2.1866 < 1.6449  we REJECT the null hypothesis


Anonymous
Goes above and beyond expectations!

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