Time remaining:
solve over the interval (0, 2pi) (root3-cotx)(2-cscx)=0

label Mathematics
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Trigonometry problem

Apr 8th, 2015

You already have the factors, so roots are easily found:

sqrt(3) - cotx = 0

cotx = sqrt(3)

tanx = 1/sqrt(3)

x = tan^-1(1/sqrt(3)) = pi/6, 7pi/6

2 - cscx = 0

cscx = 2

sinx = 1/2

x = sin^-1(1/2) = pi/6, 5pi/6

so the full solution is

x =  pi/6, 5pi/6, 7pi/6


Apr 8th, 2015

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Apr 8th, 2015
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Apr 8th, 2015
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