A regular hexagon is inscribed in a circle with a radius of 4 ft . Find the a

Mathematics
Tutor: None Selected Time limit: 1 Day

Apr 8th, 2015

The square of a circle is π*r^2. The square of the hexagon is 6*(1/2)*r*(sqrt(3)/2)
(6 triangles, 1/2*base*height).

So, S = π*r^2 - 6*(1/2)*r*(sqrt(3)/2) = r^2*(π - 3sqrt(3)/2) = 16*(π - 3sqrt(3)/2).
ft^2, if course.

Apr 8th, 2015

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Apr 8th, 2015
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Apr 8th, 2015
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