The square of a circle is π*r^2. The square of the hexagon is 6*(1/2)*r*(sqrt(3)/2)(6 triangles, 1/2*base*height).
So, S = π*r^2 - 6*(1/2)*r*(sqrt(3)/2) = r^2*(π - 3sqrt(3)/2) = 16*(π - 3sqrt(3)/2).ft^2, if course.
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