Let f(x) = 8(x-6)^(2/3) + 8

A) Find all critical values

B) Where is f(x) increasing?

C) Where is f(x) decreasing?

D) List the x values of all local maxima of f

E) List the x values of all local minima of f

A). f ' x =. 16/3 (x-6) ^2/3 +8 for critical value, set this. Equal. To 0

The critical value of x = infinity.

B) f(x) increases for x >6

C). f (x) is 0 at x= 0 so it does not decrease

D). local maxima at x= 6 local maxima is 8

E). There is no local minimal is at x = infinity

This answer was not correct. May double check work

Sorry. The critical value comes to x= 7

f (x) decreases for x> 6

Local maxima is 8+8 =16

Local minimal =8

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