Let f(x) = 8(x-6)^(2/3) + 8
A) Find all critical values
B) Where is f(x) increasing?
C) Where is f(x) decreasing?
D) List the x values of all local maxima of f
E) List the x values of all local minima of f
A). f ' x =. 16/3 (x-6) ^2/3 +8 for critical value, set this. Equal. To 0
The critical value of x = infinity.
B) f(x) increases for x >6
C). f (x) is 0 at x= 0 so it does not decrease
D). local maxima at x= 6 local maxima is 8
E). There is no local minimal is at x = infinity
This answer was not correct. May double check work
Sorry. The critical value comes to x= 7
f (x) decreases for x> 6
Local maxima is 8+8 =16
Local minimal =8
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