Let f(x) = -x^4 - 3x^3 + 2x - 1
Find the open intervals on which f is concave up
Find the open intervals on which f is concave down
Determine the x-coordinates of all inflection points of f
The derivative of f(x) is f '(x) = - 4x^3 - 9x^2 + 2.
The second derivative of f(x) is f ''(x) = -12x^2 - 18x = -6x(2x + 3). Note that f ''(x) = 0 at the points x = 0 and
x = -3/2. Since f ''(x) < 0 for x > 0 and for x < -3/2, the intervals on which f is concave down are (- infty, - 3/2) and (0, + infty).
Since f ''(x) > 0 for -3/2 < x < 0, the interval on which f is concave up is (-3/2, 0).
The inflection points are at x = 0 and x = -3/2 where the f '' changes its sign.
Content will be erased after question is completed.
Enter the email address associated with your account, and we will email you a link to reset your password.
Forgot your password?