Differentiation conditions help

Calculus
Tutor: None Selected Time limit: 1 Day

Apr 8th, 2015

(a) T because f decreases on 0 < x < 2

(b) F because f does not increase everywhere on x > 2

(c) T because f is concave down everywhere on 0 < x < 1

(d) T because f is concave up on 1 < x < 4

(e) T because f is concave down on x > 4

(f) Two inflection points are x = 1 and x = 4.

Apr 8th, 2015

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Apr 8th, 2015
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Apr 8th, 2015
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