The half-life of plutonium-239 is 24110 yrs. Of

an original mass of 88 g, how much remains

after 1.49482 × 10^5 yrs?

Answer in units of g.

The mass of radioactive element can be expressed by the formula

m(t) = m_{0} (1/2)^{T/T}_{0} , where m_{0} is the initial mass, T_{0} is the half-life and T is the time elapsed in years.

Thus m(1.49482×10^{5}) = 88 * (1/2)^{149482/24110 }= 1.2 g

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