how much energy will be needed to heat 35.7 gal of water from 22.0C to 110.0C? (not that 1.00 gal weighs 3.77 kg and that water has a specific heat capacity of 4.184 j/g C)
Energy needed = mass of water x sp heat x temp diff.
=( 35.7 x 3.77 ) kg x 4.184 kJ/kg C x ( 110-22) C
=. 49554.6 KJ (kilo joule)
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