final temperature of the water

Chemistry
Tutor: None Selected Time limit: 1 Day

A 100.0 g sample of water at 27.0°C is poured into a 70.3 g sample of water at 89.0°C. What will be the final temperature of the water?

Apr 9th, 2015

The best way to approach these particular problems is to calculate the total amount of calories and divide that by the mass of the final sample. Calories is the amount of energy required to raise the temp of one gram of water by 1 degree Celsius. So the calorie count for the first sample is 100.0 multiplied by 27.0 = 2700 cal and the second sample is 70.3 multiplied by 89.0 = 6256.7. The total calorie count for the final sample is 8956.7 cal, and the total mass of the final sample is 100.0 + 70.3 = 170.3. So the temp is 8956.7/170.3 = 52.59 degrees Celsius. Hope this helps.

Apr 9th, 2015

Are you studying on the go? Check out our FREE app and post questions on the fly!
Download on the
App Store
...
Apr 9th, 2015
...
Apr 9th, 2015
Dec 5th, 2016
check_circle
Mark as Final Answer
check_circle
Unmark as Final Answer
check_circle
Final Answer

Secure Information

Content will be erased after question is completed.

check_circle
Final Answer