Probability questions
Mathematics

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In a population of 3000 people, 70% own bicycles; of those, 49% get to work by car. By contrast. 76% of the population that doesn't own bicycles get to work by car.
(a) We can divide the population into four types base on their bike ownership and car use. How many people are in each type?
(b) Suppose you select a car commuter at random from the population. What is the probability that they own a bike?
Can you show me what you need to do to solve completely please?
a) we can divide them int four types,they are
1)bicycle owners that go to work in car
there are 70/100 *3000=2100 bicycle owners and among 2100 ,49%use car to go to work
that is 1029.............1029 peoples are in this type
2)bicycle owners that dont go to work in car
the remaining dont use car.....that is 21001029
=1071 peoples are in this type
3)not having bicycle but go to work in car
76% of 900 peoples are in this type
=684 peoples are in this type
4)not having bicycle and dont use car to go to work
900 684peoples are in this type
=216 peoples are in this type
b)
this is the propability of a car commuter having bike.......
there are 1029 car commutators having bike out of 1029+684=1713...car commutators...
so propability=1029/1713
=0.6........................................answer
HOPE YOU UNDERSTOOD .......THANK YOU
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