Your new designer chair has an S-shaped tubular metal frame that behaves just like a spring. When your friend, who weighs 610 N, sits on the chair, it bends downward 4 cm. What is the spring constant for this chair?

We can use Hooke's law to solve the problem

Here spring chair compress downward by 4 cm = 0.04 m and friend weigh 610 N that is force.

so Hooke's law F = -kX

here k is constant

-k = F / X = 610 / 0.04

spring constant = - 15250 Newton/meter

Thanks

how would you put 15250 in significant digits of 3?

152.50 KN/M

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