When 11.12 g of neon is combined in a 100 L container at 80oC with 9.59 g of argon, what is the mol

Chemistry
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When 11.12 g of neon is combined in a 100 L container at 80oC with 9.59 g of argon, what is the mole fraction of argon?
Apr 9th, 2015

Molecular mass of Ar = 40

Molecular mass of Ne = 20

Number of moles of Ar = 9.59/40 = 0.239

Number of moles of Ne = 11.12/20= 0.556

Mole fraction of argon = 0.239/ ( 0.239 + 0.556) = 0.3............Answer

Apr 9th, 2015

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