I NEED HELP
FOR OTHER ONE PRIVATE MESSAGE ME!For a ship moving against the current, it takes 9 hours to cover a distance of 113.4 miles. How much does it take this ship to return if the rate of the current is 1.9 mph?
v = the rate of the ship in still water
c = 1.9 mph the rate of the current
t1 = 9 hr the time of the travel against the current
d = 113.4 mi the distance of the travel against the current (in each direction)
t2 = the time of the return trip traveling with the current
the speed of the ship traveling with the current is: v + c
the speed of the ship traveling against the current is: v - c
since speed = distance/time follows distance = speed*time
traveling with the current:
(v + c)*t1 = d
(v + 1.9)*9 = 113.4 divide both sides by 9
v + 1.9 = 113.4/9
v = 113.4/9 - 1.9
traveling against the current:
(v - c)*t2 = d
(v - 1.9)*t2 = 113.4
by solving the system of equations:
t2 = 12.89 hr
If I have helped, please click on "best". Thanks!
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