Oh okay. Thank you! I found out what I did wrong. For this question would I use the equation with ln? For the 18 hour one I got 97.16% The 1 day I got 46.68%. The 5 half-lives I got 5.61%. But I got it wrong. Im not sure how to do it
Technetium-99m, an important radionuclide in medicine, has a half-life of 6.0 hours. What percentage of a sample of technetium-99m will remain undecayed after the following times?
There are two half-reactions: Cu(s) -> Cu^+ (aq) + e^- (oxydation, anode, reduction potential E anode = 0.52 V) and Ag^+ (aq) + e^- -> Ag (s) (reduction, cathode, reduction potential E cathode = 0.80 V. The cell will give E cathode - E anode = 0.80 - 0.52 = 0.28 V for a standard cell emf.