100 mL of a .4 L solution of KI (aq) is used as a reactant in an experiment. When
the experiment is done, the chemist measures the rate of the reaction that
involves KCl. Then chemist boils down the remaining KI solution to 80 mL, cools it
to the original temperature and uses it to do so a second trial of the same
a. Will the reaction rate of the second trial be smaller, remain the same or increase
over the rate of the first trial?
Simple..No reaction would take place between potassium iodide and potassium chloride ...but once potassium iodide (KI)is heated to boiling and left to cool,itvreact faster but not occurs with potassium chloride