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Find the length of the rectangl?

Algebra
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The length of a rectangle is 2cm more than its width.if the perimeter of the rectangle is 52cm, find the length of the rectangle?

Apr 10th, 2015

It is stated that length (L) is 2 more than the width (w)

L = w + 2

Perimeter of a rectangle is given as

P = 2L + 2w

Using the information from the first equation

P = 2(w + 2) + 2w = 52

2w + 4 + 2w = 52

4w + 4 = 52

4w = 48

w = 12 cm

The questions asks to find the length.  This can be accomplished by using the first equation and the length of the width from directly above.

L = 12 + 2

L = 14 cm

Apr 10th, 2015

The answers listed are 

18cm

8cm

52cm

16cm

How did get 14

Apr 10th, 2015

I have rechecked the math.  14 should be the correct answer as none of the others listed would give the correct perimeter.  Please make sure your original post was accurate and there was not a typo in the numbers.  Also it would help if you could please take a picture or screen shot of the original question, so that I can see it in its entirety.  From that I should be able to find the error.

Apr 10th, 2015

The length of the rectangle is 2 cm more than twice its width. If the perimeter of the rectangle is 52 cm, find the length of the rectangle?

Apr 13th, 2015

Alright. In the original you missed the twice the width part.

So following the instructions above here is the solution.

L = 2w + 2

P = 2w + 2L = 52

2w + 2(2w + 2) = 52

2w + 4w + 4 = 52

6w = 48

w = 8 cm

L = 2*8 + 2

L = 18 cm

Final answer: the length is equal to 18 cm.

Apr 13th, 2015

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