I NEED HELP!
For a ship moving against the current, it takes 9 hours to cover a distance of 113.4 miles. How much does it take this ship to return if the rate of the current is 1.9 mph?
1. Let x = speed of the ship without current
Then, moving against the current
x - 1.9 = 113.4/9
x - 1.9 = 12.6
x = 14.5 mph
moving with the current the ship's speed is 14.5 + 1.9 = 16.4mph
therefore the time it takes to return is
113.4/16.4 = 6.9 hours
2. Let x = rate of the first train
Let y = rate of the second train
then, x = y + 26
distance = (rate)(time)
For the first train
distance = 2.8x
For the second train
but both distances are the same, so
2.8x = 4.67y
Now substitute x for y+26
2.8(y+26) = 4.67y
2.8y + 72.8 = 4.67y
1.87y = 72.8
y = 38.93 mph
so, the distance = (38.93)(4.67) = 181.8 miles
Hey, umm, sorry, but the second one wasnt right. Could you do it again? Thanks, and sorry for all the hassle
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