a hydraulic piston lift consists of a 25 cm radius piston that is lifting a car that has a weight 3200 N. How much force must be applied to the other piston if it has a radius of 5 cm.
A1/A2 = F2/F1 = (r1/r2)^2 = (5/25)^2 = 1/25
F2 = 1/25*3200N = 128 N
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