In the hydraulic system shown in Figure 15-28 the piston on the left has

Physics
Tutor: None Selected Time limit: 1 Day

Apr 10th, 2015

Pressure on the left = 1.7*g / [π* 0.0045^2] 
P2 the Pressure on the right is proportiional to 2.7*g/ [* π* 0.012^2] 
P1 - P2 = [g /π] *[(1.7/0.0045^2) - (2.7 / 0.012^2)] = h d g 
h = {(1.7/0.0045^2) - (2.7 / 0.012^2)} / [750* π] 
= 27.67m 

Apr 10th, 2015

Pressure on the left = 1.7*g / [π* 0.0045^2] 
P 2 the Pressure on the right is proportional to 2.7*g/ [* π* 0.012^2] 
P1 - P2 = [g /π] *[(1.7/0.0045^2) - (2.7 / 0.012^2)] = h d g 
h = {(1.7/0.0045^2) - (2.7 / 0.012^2)} / [750* π] 
= 27.67 m 

Apr 10th, 2015

the answer was incorrect

Apr 11th, 2015

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