A man has 30 coins in his pocket, all of which are dimes and quarters. If the total value of his change is 540 cents, how many dimes and how many quarters does he have?
let the number of dimes and quarters are x and y respectively, then we have
x+y = 30
10x+25y = 540
from the first eq,
x = 30-y
plugging it into the second eq,
10(30-y)+25y = 540
300-10y+25y = 540
15y = 540-300= 240
y = 16
x = 14
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