t = (dbar/s_{d} )* sqrt(n)

t = -51.4286 /26.09506 *sqrt(7)= -5.21429

I have retained the accuracy and then rounded to 3 decimals

If we work with -51.4/26.1 * sqrt(7) then it will be -5.210

I am not quite sure how they feed the answer

If we consider differ (score after -score prior ) then t = 5.214

51.4/26.1 * sqrt(7) = 5.210

That is why I have provided all the possibilities

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