critical value for t with 6 df = 1.943
Since we are having left sided alternative ,
the decision rule is as followes:
If computed t is < -1.943 then we reject the null hypothesis.
Otherwise we do not reject the null hypothesis.
I prefer the above decision rule
If we take diff as (score after-score prior) then
the rule is:
If t > 1.943 then reject the null hypothesis.
Any way I am posting since I do not know how they feed the answer
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