critical value for t with 6 df = 1.943

Since we are having left sided alternative ,

the decision rule is as followes:

If computed t is < -1.943 then we reject the null hypothesis.

Otherwise we do not reject the null hypothesis.

I prefer the above decision rule

If we take diff as (score after-score prior) then

the rule is:

If t > 1.943 then reject the null hypothesis.

Any way I am posting since I do not know how they feed the answer

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