Mathematics
Columbia Southern University Elementary Algebra Problems

Columbia Southern University

Question Description

I need assistance completing 4-5 algebra assignments.

Final Answer

Unit 8 solution is attached.Please, let me know if you have any questions.

1.

π‘Žπ‘Ž+𝑏𝑏
10

=

79+11
10

90

= 10 = πŸ—πŸ—

2. 6(𝑒𝑒 + 8 + 8𝑣𝑣) = πŸ”πŸ”πŸ”πŸ” + πŸ’πŸ’πŸ’πŸ’ + πŸ’πŸ’πŸ’πŸ’πŸ’πŸ’
3. |𝑦𝑦| = |45| = πŸ’πŸ’πŸ’πŸ’

4. Perimeter = 11 + 8π‘₯π‘₯ + 7π‘₯π‘₯ + 9 + 6π‘₯π‘₯
= 𝟐𝟐𝟐𝟐 + 𝟐𝟐𝟐𝟐𝟐𝟐

5. 262.05 + 140 βˆ’ π‘₯π‘₯ = βˆ’35.08
π‘₯π‘₯ = 262.05 + 140 + 35.08
𝒙𝒙 = πŸ’πŸ’πŸ’πŸ’πŸ’πŸ’. 𝟏𝟏𝟏𝟏

6. βˆ’8 βˆ’ 7 + (βˆ’6) βˆ’ 5

= βˆ’8 βˆ’ 7 βˆ’ 6 βˆ’ 5 = βˆ’πŸπŸπŸπŸ

7.

22 βˆ’(βˆ’1)7

5βˆ™15βˆ’16βˆ™22 βˆ’42

=

4βˆ’(βˆ’1)

75βˆ’16Γ—4βˆ’16

4+1
5
=
=
= βˆ’πŸπŸ
75 βˆ’ 64 βˆ’ 16 βˆ’5

8. 4(8π‘žπ‘ž βˆ’ 5) βˆ’ [3(4π‘žπ‘ž βˆ’ 3) + 4]
= 32π‘žπ‘ž βˆ’ 20 βˆ’ [12π‘žπ‘ž βˆ’ 9 + 4]
= 32π‘žπ‘ž βˆ’ 20 βˆ’ [12π‘žπ‘ž βˆ’ 5]
= 32π‘žπ‘ž βˆ’ 20 βˆ’ 12π‘žπ‘ž + 5
= 𝟐𝟐𝟐𝟐𝟐𝟐 βˆ’ 𝟏𝟏𝟏𝟏
1

1

𝟏𝟏

9. π‘₯π‘₯ = βˆ’ 5 + 10 = βˆ’ 𝟏𝟏𝟏𝟏
3

10. 5 𝑑𝑑 βˆ’ 4 = 5

3𝑑𝑑 βˆ’ 20 = 25
3𝑑𝑑 = 45
𝒕𝒕 =

πŸ’πŸ’πŸ’πŸ’
= 𝟏𝟏𝟏𝟏
πŸ‘πŸ‘

11. 6(π‘₯π‘₯ + 8) = 6(8 + π‘₯π‘₯)
6π‘₯π‘₯ + 48 = 48 + 6π‘₯π‘₯

B: All the numbers are solution:
Identity

1

12. b = 2 gq
13.

π’ˆπ’ˆ =
7.92
33

𝟐𝟐𝟐𝟐
𝒒𝒒

Γ— 100% = 𝟐𝟐𝟐𝟐%

14. π‘₯π‘₯ + (π‘₯π‘₯ + 1) + (π‘₯π‘₯ + 2) = 126
3π‘₯π‘₯ + 3 = 126
3π‘₯π‘₯ = 123
π‘₯π‘₯ = 41

π‘₯π‘₯ + 1 = 42,

π‘₯π‘₯ + 2 = 43

Their ages are 41, 42 and 43.
15. First angle: 2x
Second angle: x
Third angle: π‘₯π‘₯ + 72

2π‘₯π‘₯ + π‘₯π‘₯ + (π‘₯π‘₯ + 72) = 180
4π‘₯π‘₯ + 72 = 180
4π‘₯π‘₯ = 108
π‘₯π‘₯ =

108
= 27
4

First angle: 𝟐𝟐𝟐𝟐 = 𝟐𝟐 Γ— 𝟐𝟐𝟐𝟐 = πŸ“πŸ“πŸ“πŸ“πŸŽπŸŽ
Second angle: 𝒙𝒙 = 𝟐𝟐𝟐𝟐𝟎𝟎

Third angle: 𝒙𝒙 + πŸ•πŸ•πŸ•πŸ• = 𝟐𝟐𝟐𝟐 + πŸ•πŸ•πŸ•πŸ• = πŸ—πŸ—πŸ—πŸ—πŸŽπŸŽ

16. 3(π‘Ÿπ‘Ÿ βˆ’ 4) + 1 > 4(π‘Ÿπ‘Ÿ + 2) βˆ’ 17
3π‘Ÿπ‘Ÿ βˆ’ 4 + 1 > 4π‘Ÿπ‘Ÿ + 8 βˆ’ 17
3π‘Ÿπ‘Ÿ βˆ’ 3 > 4π‘Ÿπ‘Ÿ βˆ’ 9

βˆ’3 + 9 > 4π‘Ÿπ‘Ÿ βˆ’ 3π‘Ÿπ‘Ÿ
6 > π‘Ÿπ‘Ÿ

𝒓𝒓 < πŸ”πŸ”

17. 35 + 0.22π‘šπ‘š ≀ 90
0.22π‘šπ‘š ≀ 90 βˆ’ 35
0.22π‘šπ‘š ≀ 55

π’Žπ’Ž ≀ 𝟐𝟐𝟐𝟐𝟐𝟐 π’Žπ’Žπ’Žπ’Žπ’Žπ’Žπ’Žπ’Žπ’Žπ’Ž

D

18. The person weighs less than or equal
to 180 Ibs
19. 𝑦𝑦 + 2π‘₯π‘₯ = 7

Yes, (1, 5) is a solution

Yes (4, -1) is a solution.
Yes (-1, 9) is a solution.
1

20. 𝑦𝑦 βˆ’ βˆ’ 6 π‘₯π‘₯

The agenc...

uoscar (3983)
Boston College

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