Mathematics
Columbia Southern University Elementary Algebra Problems

Columbia Southern University

### Question Description

I need assistance completing 4-5 algebra assignments.

Unit 8 solution is attached.Please, let me know if you have any questions.

1.

ππ+ππ
10

=

79+11
10

90

= 10 = ππ

2. 6(π’π’ + 8 + 8π£π£) = ππππ + ππππ + ππππππ
3. |π¦π¦| = |45| = ππππ

4. Perimeter = 11 + 8π₯π₯ + 7π₯π₯ + 9 + 6π₯π₯
= ππππ + ππππππ

5. 262.05 + 140 β π₯π₯ = β35.08
π₯π₯ = 262.05 + 140 + 35.08
ππ = ππππππ. ππππ

6. β8 β 7 + (β6) β 5

= β8 β 7 β 6 β 5 = βππππ

7.

22 β(β1)7

5β15β16β22 β42

=

4β(β1)

75β16Γ4β16

4+1
5
=
=
= βππ
75 β 64 β 16 β5

8. 4(8ππ β 5) β [3(4ππ β 3) + 4]
= 32ππ β 20 β [12ππ β 9 + 4]
= 32ππ β 20 β [12ππ β 5]
= 32ππ β 20 β 12ππ + 5
= ππππππ β ππππ
1

1

ππ

9. π₯π₯ = β 5 + 10 = β ππππ
3

10. 5 π‘π‘ β 4 = 5

3π‘π‘ β 20 = 25
3π‘π‘ = 45
ππ =

ππππ
= ππππ
ππ

11. 6(π₯π₯ + 8) = 6(8 + π₯π₯)
6π₯π₯ + 48 = 48 + 6π₯π₯

B: All the numbers are solution:
Identity

1

12. b = 2 gq
13.

ππ =
7.92
33

ππππ
ππ

Γ 100% = ππππ%

14. π₯π₯ + (π₯π₯ + 1) + (π₯π₯ + 2) = 126
3π₯π₯ + 3 = 126
3π₯π₯ = 123
π₯π₯ = 41

π₯π₯ + 1 = 42,

π₯π₯ + 2 = 43

Their ages are 41, 42 and 43.
15. First angle: 2x
Second angle: x
Third angle: π₯π₯ + 72

2π₯π₯ + π₯π₯ + (π₯π₯ + 72) = 180
4π₯π₯ + 72 = 180
4π₯π₯ = 108
π₯π₯ =

108
= 27
4

First angle: ππππ = ππ Γ ππππ = ππππππ
Second angle: ππ = ππππππ

Third angle: ππ + ππππ = ππππ + ππππ = ππππππ

16. 3(ππ β 4) + 1 > 4(ππ + 2) β 17
3ππ β 4 + 1 > 4ππ + 8 β 17
3ππ β 3 > 4ππ β 9

β3 + 9 > 4ππ β 3ππ
6 > ππ

ππ < ππ

17. 35 + 0.22ππ β€ 90
0.22ππ β€ 90 β 35
0.22ππ β€ 55

ππ β€ ππππππ ππππππππππ

D

18. The person weighs less than or equal
to 180 Ibs
19. π¦π¦ + 2π₯π₯ = 7

Yes, (1, 5) is a solution

Yes (4, -1) is a solution.
Yes (-1, 9) is a solution.
1

20. π¦π¦ β β 6 π₯π₯

The agenc...

uoscar (3983)
Boston College
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