Using the Conjugate Roots Theorem, factor the polynomial function completely

label Algebra
account_circle Unassigned
schedule 1 Day
account_balance_wallet $5

f(x)=x^6-73x^4-657x^2+729

Oct 21st, 2017

let x^2=A

f(x)=a^3-73a^2-657a+729

from observation, a=1 is a root

therefore

x^2=1

x= +/- 1

on further analysis, x=9 and x=3i also satisfy the equation.

Using the Conjugate theorem, 

x=-3i is also a root of the equation. So is x=-9

Hence using the above Values,

the factored polynomial is

(x−1)(x+1)(x−9)(x+9)(x+3i)(x-3i)

that is

(x−1)(x+1)(x−9)(x+9)(x^2+9)


Apr 11th, 2015

Studypool's Notebank makes it easy to buy and sell old notes, study guides, reviews, etc.
Click to visit
The Notebank
...
Oct 21st, 2017
...
Oct 21st, 2017
Oct 21st, 2017
check_circle
Mark as Final Answer
check_circle
Unmark as Final Answer
check_circle
Final Answer

Secure Information

Content will be erased after question is completed.

check_circle
Final Answer