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##### subtracting polynomials

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(4r^3+3r^4) - (r^4-5r^3)

Apr 11th, 2015

(4r^3+3r^4) - (r^4-5r^3) = 4r^3 + 3r^4 - r^4 + 5r^3

= 3r^4 - r^4 + 4r^3 + 5r^3

= 2^4 + 9r^3                      answer

Apr 11th, 2015

what is the answer

Apr 11th, 2015

Sorry

(4r^3+3r^4) - (r^4-5r^3) = 4r^3 + 3r^4 - r^4 + 5r^3

= 3r^4 - r^4 + 4r^3 + 5r^3

= 2r4 + 9r^3

Apr 11th, 2015

2^4+9r^3 is the answer 26r

Apr 11th, 2015

(4r^3+3r^4) - (r^4-5r^3) = 4r^3 + 3r^4 - r^4 + 5r^3

= 3r^4 - r^4 + 4r^3 + 5r^3

= 2r^4 + 9r^3

= r^3(2r + 9)

Apr 11th, 2015

(4r^3+3r^4) - (r^4-5r^3) = 4r^3 + 3r^4 - r^4 + 5r^3

= 3r^4 - r^4 + 4r^3 + 5r^3

= 2r^4 + 9r^3

= r^3(2r + 9)

Apr 11th, 2015

what is the answer

Apr 11th, 2015

can this be reduced anymore, im trying to figure it out for my school student whom cannot even begin to understand.

how about a simple step by step example on how to solve it can you give me that.

Apr 11th, 2015

Both answers are correct.

You can use   = 2r^4 + 9r^3

or

= r^3(2r + 9)            You can take r^3 as common.

Apr 11th, 2015

lets get this strait,

I was taught simple do whats in brackets first.

example 4r^3 +3r^4 =1278r+27r=1305r-

125r=1180r

Apr 11th, 2015

If you see your question, power are given on r(alphabet) not on figure.

Apr 11th, 2015

not to solve but show equation

Apr 11th, 2015

need to know rules of how to answer this

Apr 11th, 2015

( 3a^2+1) - (4+2a^2)

1-4 +3a^2+2a^2

1-4+5a^2 is this the answer?

Apr 11th, 2015

( 3a^2+1) - (4+2a^2)

3a^2 + 1 - 4 - 2a^2

3a^2 - 2a^2 + 1 - 4

Apr 11th, 2015

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Apr 11th, 2015
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Apr 11th, 2015
Dec 8th, 2016
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