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electrostatics physics

Physics
Tutor: None Selected Time limit: 1 Day

An uncharged molecule of DNA (deoxyribonucleic

acid) is 2.17 µm long. The ends

of the molecule become singly ionized so that

there is a charge of −1.6 × 10−19 C on one end

and +1.6 × 10−19 C on the other. The helical

molecule acts like a spring and compresses

1.3% upon becoming charged.

Find the effective spring constant of the

molecule. The value of Coulomb’s constant is

8.98755 × 109 N · m^2

/C^2

Apr 11th, 2015

e = 1.6x10^-19 C 

F = kQ²/r² 
F = (8.98755x10^9)(1.6x10^-19)²/(2.17x10^-6)² 
F = 4.886x10^-17 N 

F = Kx 
x = 0.0108(2.17x10^-6) 

4.886x10^-17 = K(0.0108(2.7x10^-6) 
K = 2.085c10^-9 N/m

Apr 11th, 2015

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Apr 11th, 2015
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