What is the final Temperature of the water mixture
Heat balance is: heat gained by 50g sample = heat lost by 29 g water
So m1 x cp x temp. Diff. Of 1 = m2 x cp x temp diff of 2
m1 x temp. Diff of 1 = m2 x temp diff of 2
Let t be the final temp of water mixture.
50 g ( t-25 ) C = 29 g ( 45 -t) C
50 t -1250 = 1305 -29 t
Therefore t = 2555/79 = 32.34 C
Answer : final temp. Is 32.34 C
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