What is the final Temperature of the water mixture

Heat balance is: heat gained by 50g sample = heat lost by 29 g water

So m1 x cp x temp. Diff. Of 1 = m2 x cp x temp diff of 2

m1 x temp. Diff of 1 = m2 x temp diff of 2

Let t be the final temp of water mixture.

50 g ( t-25 ) C = 29 g ( 45 -t) C

50 t -1250 = 1305 -29 t

Therefore t = 2555/79 = 32.34 C

Answer : final temp. Is 32.34 C

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Niru

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