2) Clearly BC is just extended pat of AB, and CE||DB hence BECD is a parellogram

AC congruent BD is given , and since BECD is a parellogram BD = CE

Hence, AC = CE.

Since triangle BFD is congruent to AFC, diagonals are given equal. also F will be on the point of intersection, such that BD and AC are divided in the ratio similarly.

I am saying can you put it in 1$ bid again....cause I have already solved one question from this sheet, which when you will best I will ge t 1$. For 2 questions I guess You are supppose to give $2