In triange ABF and CDF
Angle B = Angle D ( Both 90 degrees )
Angle AFC = Angle BFD ( Bothe 90 degree )
Subtract Angle BFC from angle AFC and BFD both we get,
Angle AFB = Angle CFD
Clearly since 2 angles of triange ABF and CDF are equal, 3 rd angles will be equal by angle sum property.
Hence, both the triangles are similar,
ABF ~ CDF
Since triangles are similar, raio of there sides will be same.
AB / CD = AF / CF
AB x CF = AF x CD
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What postulates/theorems would "Subtract angle BFC from angle AFC and BFD both we get Angle AFB = Angle CFD
It is for a proof
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