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Mathematics
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Apr 12th, 2015

Factor x2 – x – 20 = (x – 5) (x + 4). Then

ln [(x2 – x – 20) / (x + 7)3 ]1/4 =

1/4 ln [(x – 5) (x + 4) / (x + 7)3 ] =        use the properties ln(ab) = ln a + ln b,  ln(a/b) = ln a – ln b, 

                                                            and ln an = n lna

(1/4)ln(x – 5) + (1/4) ln(x + 4) – (3/4) ln(x + 7)


Apr 12th, 2015

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Apr 12th, 2015
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Apr 12th, 2015
Dec 5th, 2016
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