a school is building a rectangular soccer field that has an area of 6000 square yards. The soccer field must be 40 yards longer than its width. Determine algebraically the dimensions of the soccer field, in yards
assume the width is x, then length is x+40 yards
so the area of the rectangle is x(x+40)=6000, x^2+40x-6000=0, x=-100 (ignore), x=60
so the width is 60 yards, length is 100 yards.
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