If it takes 54 mL of 0.1 M NaOH to neutralize 125 mL of an HCL solution, what is the concentration of the HCl?
NaOH+HCl = NaCl+H2O
the mole ratio fo NaOH and HCl is 1:1,
0.054*0.1M = 0.125*x
x = 0.0054/0.125 = 0.0432 M
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