The equation of the reaction is NaOH + HCl -> NaCl + H2O.
25 mL of 0.05 M HCl solution contain 0.025 L * 0.05 mol/L = 0.00125 mol of HCl.
Since the coefficients in the equation for HCl and NaOH are equal, for neutralization we need 0.00125 mol of NaOH in 345 mL = 0.345 L of a solution. The concentration of the solution is 0.00125/0.345 = 0.00362 M or 3.62*10^(-3) M solution of NaOH.
Apr 12th, 2015
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