I need help with a difficult Algebra question.

Algebra
Tutor: None Selected Time limit: 1 Day

A car and a motorcycle leave at noon from the same location, heading in the same direction. The average speed of the car is 30 mph slower than twice the speed of the motorcycle. In two hours, the car is 20 miles ahead of the motorcycle. Find the speed of both the car and the motorcycle, in miles per hour.

Apr 12th, 2015

speed of motor cycle = 40 miles/ hr

speed of car =(2×40-30)=50 miles/ hr



Please just reply to this question I will send you the complete procedure from computer. ....

Apr 12th, 2015

Thank you so much for all of your help.

Apr 12th, 2015

Hello

Let the speed of Motor cycle = x Miles/hr (mph)

Then car speed will be  :    (2x-30)

Distance traveled = Speed * time

therefore , distance traveled by car in 2 hrs will be  = 2(2x-30).

&  distance traveled by motorcycle  in 2 hrs will be  = (2x)

Since both are traveling in same direction therefore difference will be 20 miles 

hence we can write,   2(2x-30)-2x = 20

solving we get, 4x-60-2x= 20

or, 2x = 80

or, x = 80/2 = 40 miles per hr  (Motorcycle)

Car speed  =(2x-30) = (2*40-30) = 80-30 =50 mph


Please ask if you have any doubt !!


Apr 12th, 2015

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Apr 12th, 2015
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