what volume of 0.500 M hydrochloric acid is required to exactly neutralize 40.00 mL 0.150 M NaOH?
HCl+NaOH = NaCl+H2O
The ratio of HCL and NaOH is 1 to 1
let volume be x ml, then we have
x*0.5 = 40*0.150
x = 12 ml
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